X^2+9x-246=0

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Solution for X^2+9x-246=0 equation: 



X^2+9X-246=0

a = 1; b = 9; c = -246;
Δ = b2-4ac
Δ = 92-4·1·(-246)
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1065}}{2*1}=\frac{-9-\sqrt{1065}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1065}}{2*1}=\frac{-9+\sqrt{1065}}{2}
$

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